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@aktowns
Created November 19, 2010 12:53
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(*
Problem 1
If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000.
*)
[1..1000]
|> List.filter (fun n -> (n%3) = 0 || (n%5) = 0)
|> List.fold (+) 0
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