Created
September 19, 2019 16:53
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# Like choicesWithNames(), but returns a data frame of value, label, and | |
# optgroup columns. This rectangular view could also be thought of as the set | |
# of paths into the choicesWithNames() tree. | |
# | |
# For example, given a choices argument like this: | |
# | |
# list(a = 1, B = list(B = 2), c = list(3)) | |
# | |
# choicesWithNames() would return a tree like this: | |
# | |
# list(a = "1", B = list(B = "2"), c = "3") | |
# | |
# and choicesWithNamesRectangle() would return an equivalent "rectangular" | |
# representation as a data frame: | |
# | |
# label value optgroup | |
# a 1 | |
# B 2 B | |
# c 3 | |
choicesWithNamesRectangle <- function(choices) { | |
label <- character() | |
value <- character() | |
optgroup <- character() | |
choiceTree <- choicesWithNames(choices) | |
for (i in seq_along(choiceTree)) { | |
# If this element is a list, then it's an group. Each sub-element | |
# should be added with a group name. | |
if (is.list(choiceTree[[i]])) { | |
for (j in seq_along(choiceTree[[i]])) { | |
label[length(label)+1] <- names(choiceTree[[i]])[[j]] | |
value[length(value)+1] <- choiceTree[[i]][[j]] | |
optgroup[length(optgroup)+1] <- names(choiceTree)[[i]] | |
} | |
# If this element isn't a list, then it's a leaf node with no group. | |
} else { | |
label[length(label)+1] <- names(choiceTree)[[i]] | |
value[length(value)+1] <- choiceTree[[i]] | |
optgroup[length(optgroup)+1] <- "" | |
} | |
} | |
data.frame( | |
label = label, | |
value = value, | |
optgroup = optgroup, | |
stringsAsFactors = FALSE, | |
row.names = NULL | |
) | |
} |
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