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@alex3305
Last active August 29, 2015 14:02
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Java 8 simple input validation with quotes
/**
* Function that checks whether the command line input is valid. This
* method can handle input with spaces that are escaped inside
* quotation marks (either " or '). However this method will throw
* an Exception when either the input is empty or when the input
* is malformed.
*
* Malformed input occurs when there are an odd number of quotation
* marks in the input string, but only if there are more than one.
*
* @param input Input that should be validated.
* @return Validated input as an array.
* @throws NullPointerException When the input is empty.
* @throws IllegalArgumentException When there are an odd number
* of quotation marks.
*/
private final String[] getInput(String input) throws NullPointerException, IllegalArgumentException {
if (input.isEmpty()) {
throw new NullPointerException("Input cannot be empty.");
}
if (input.chars().filter(c -> (c == ' ')).count() == 0) {
return new String[] { input };
}
if (input.chars().filter(c -> (c == '"' || c == '\'')).count() % 2 == 1) {
throw new IllegalArgumentException("Malformed input, please check your syntax.");
}
int numberOfQuotes = 0;
String currentCommand = "";
ArrayList<String> args = new ArrayList<>();
for (char c : input.toCharArray()) {
if (c == '"' || c == '\'') {
numberOfQuotes++;
continue;
}
if (c == ' ' && numberOfQuotes % 2 == 0) {
args.add(currentCommand);
currentCommand = "";
continue;
}
currentCommand += c;
}
if (!currentCommand.isEmpty()) {
args.add(currentCommand);
}
return args.toArray(new String[0]);
}
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