A contribution by Flambino to my question at [StackOverflow](http://codereview.stackexchange.com/questions/108617/most-efficient-fizzbuzz-solution-in-ruby#comment199713_108625)

FlambinoFizzBuzzChallenge.rb

require 'benchmark'

N = Array(1..10_000_000)

def no_op(*a); end

def fizzbuzz(array)
  array.each do |number|
    divisibleBy3 = (number % 3 == 0)
    divisibleBy5 = (number % 5 == 0)

    case
    when divisibleBy3 && divisibleBy5
      no_op "FizzBuzz"
    when divisibleBy3
      no_op "Fizz"
    when divisibleBy5
      no_op "Buzz"
    else
      no_op number
    end
  end
end

puts Benchmark.measure{fizzbuzz(N)}
puts "fizzbuzz"


def super_fizzbuzz(array)
  array.each do |number|
    divisibleBy3 = (number % 3 == 0)
    divisibleBy5 = (number % 5 == 0)

    if divisibleBy3 && divisibleBy5
      no_op "FizzBuzz"
    elsif divisibleBy3
      no_op "Fizz"
    elsif divisibleBy5
      no_op "Buzz"
    else
      no_op number
    end
  end
end

puts Benchmark.measure{super_fizzbuzz(N)}
puts "super_fizzbuzz"