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Condorcet's Jury Theorem
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function choose(n, k) { | |
if (k == 0) { | |
return 1 | |
} else { | |
return (n * choose(n - 1, k - 1)) / k | |
} | |
} | |
var N = 21; | |
var T = 100; | |
var p = []; | |
for (var t = 1; t < T; t++) { | |
p.push(t * 1/T) | |
} | |
p | |
var probPasses = []; | |
for (var t = 1; t < T; t++) { | |
var prob = 0; | |
for (var k = Math.ceil(N/2); k <= N; k++) { | |
prob = prob + choose(N,k) * (p[t-1]**k) * (1 - p[t-1])**(N-k) | |
} | |
probPasses.push(Math.round(prob*100000)/100000) | |
} | |
probPasses |
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