Created
July 10, 2011 14:10
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Syntactic sugar to replace '__name__' idiom with function call
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import main | |
if main.executed(): | |
print 'Hello World' |
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if __name__ == '__main__': | |
print 'Hello World' |
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"Convenience function for programs 'main'." | |
import inspect | |
def executed(_level=1): | |
"""Return True if called in a module that is executed. | |
Inspects the '__name__' in the stack frame of the caller, comparing it | |
to '__main__'. Thus allowing the Python idiom: | |
>>> if __name__ == '__main__': | |
... pass | |
To be replace with: | |
>>> if executed(): | |
... pass | |
""" | |
stack = inspect.stack() | |
if len(stack) < _level: | |
return False | |
frame = stack[_level][0] | |
if not inspect.isframe(frame): | |
return False | |
return frame.f_globals['__name__'] == '__main__' |
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