Find runs of consecutive items in a numpy array.
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import numpy as np | |
def find_runs(x): | |
"""Find runs of consecutive items in an array.""" | |
# ensure array | |
x = np.asanyarray(x) | |
if x.ndim != 1: | |
raise ValueError('only 1D array supported') | |
n = x.shape[0] | |
# handle empty array | |
if n == 0: | |
return np.array([]), np.array([]), np.array([]) | |
else: | |
# find run starts | |
loc_run_start = np.empty(n, dtype=bool) | |
loc_run_start[0] = True | |
np.not_equal(x[:-1], x[1:], out=loc_run_start[1:]) | |
run_starts = np.nonzero(loc_run_start)[0] | |
# find run values | |
run_values = x[loc_run_start] | |
# find run lengths | |
run_lengths = np.diff(np.append(run_starts, n)) | |
return run_values, run_starts, run_lengths |
Thank you :)
Thanks! This is exactly what I needed!
Thanks! Nice work, just what I want!
膜拜大佬
Very good! Thanks.
Thanks finally a solution that works as intended
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