Created
December 1, 2012 21:03
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# Another from Programming Pearls (again, my attempt before reading | |
# the rest of the chapter). Rotate a vector left in place by some | |
# amount without using extra memory proportional to the length of the | |
# input vector and while running in in O(n) | |
def rotate_left(vec, n): | |
i = 0 | |
start = 0 | |
letter = vec[i] | |
seen = 0 | |
while True: | |
seen += 1 | |
i = (i - n) % len(vec) | |
newletter = vec[i] | |
vec[i] = letter | |
letter = newletter | |
# We've looped back to where we started | |
if i == start: | |
# Have we seen all the items in the vector yet? | |
if seen == len(vec): | |
break | |
else: | |
start = i = start+1 | |
letter = vec[i] | |
return vec | |
print "".join(rotate_left(list("abcdefgh"), 3)) | |
# Can also rotate right | |
print "".join(rotate_left(list("abcdefgh"), -2)) |
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