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sorting(true numerical sorting) names with numbers using nested list comprehension
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# sorting a list of strings whos values are ints. | |
>>> numbers = ['100','11','21','200'] | |
>>> sorted(numbers) | |
['100', '11', '200', '21'] | |
>>> | |
# Sorting that same list using list comprehension to convert the values into ints before sorting | |
>>> numbers = ['100','11','21','200'] | |
>>> sorted([int(n) for n in numbers]) | |
[11, 21, 100, 200] | |
>>> | |
# Sorting regular integers | |
>>> numbers = [100,11,21,200] | |
>>> sorted(numbers) | |
[11, 21, 100, 200] | |
>>> | |
# Using nested list comprehension to sort names with numbers - true sorting by numbers! | |
>>> import re | |
>>> images = ['img100.png','img11.png','img21.png','img200.png'] | |
>>> [ 'img'+str(n)+'.png' for n in sorted([ int(r.group(2)) for r in [re.search('(^img)(\d+)(.png)',image, re.I) for image in images] ]) ] | |
['img11.png', 'img21.png', 'img100.png', 'img200.png'] | |
>>> |
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