pythonでPOP SSLを使い大きい順に5個メッセージを表示又は削除する

show_bigmsgs_by_pop.py

#!/usr/bin/env python
# -*- coding: utf-8 -*-

import sys
import time
import poplib
import email


def get_subject(msg):
    h = email.Header.decode_header(msg.get('subject'))
    return unicode(email.header.make_header(h)).encode('utf-8')

def get_from(msg):
    h = email.Header.decode_header(msg.get('from'))
    return unicode(email.header.make_header(h)).encode('utf-8')


def get_date(msg):
    mdate = email.utils.parsedate(msg.get('date'))
    return time.strftime('%Y/%m/%d %H:%M:%S', mdate)

def get_body(msg):
    body = msg.get_payload(decode=True)
    char = msg.get_param('charset')
    return unicode(body, char, 'ignore').encode('utf-8')

argvs = sys.argv
argc = len(argvs)

print argvs
print "number of args: {0}".format(argc)
print
if (argc != 6):
    print 'Usage: # python {0} <popserver> <ssl_port> <user> <pass> <"chk"|"dele">'.format(argvs[0])
    quit()

pop = poplib.POP3_SSL(argvs[1],port=int(argvs[2]))
pop.set_debuglevel(1)
pop.user(argvs[3])
pop.pass_(argvs[4])

raw_all_list=pop.list()[1] # 2番目に文字列のリストが入っている
all_list=map( (lambda x:  x.split(' ')), raw_all_list) #文字列のリストをリストに変換して2次元配列を作る
all_list.sort(cmp=lambda x,y: cmp(int(x[1]), int(y[1]))) #メッセージサイズを整数としてsortする

target_msgs = all_list[-5:]
target_list =[]

for msg in target_msgs:
    raw_blob_list = pop.retr(int(msg[0]))[1]
    raw_blob = email.message_from_string('\n'.join(raw_blob_list))
    target_list.append([msg[0], msg[1], get_date(raw_blob), get_subject(raw_blob), get_from(raw_blob)])

for item in target_list:
    print "{0}, size: {1:>10}, {2:10},{3}".format(item[2],item[1],item[4][0:20],item[3])
    if (argvs[5]=='dele'):
        pop.dele(int(msg[0]))

if (argvs[5]=='dele'): time.sleep(10)
pop.quit()