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@amuradyan
Created April 4, 2020 02:11
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// If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
// Find the sum of all the multiples of 3 or 5 below 1000.
void doShit() {
Integer currentValue = 1;
Integer acc = 0;
while(currentValue < 1000) {
boolean imot = ((currentValue / 3) == (currentValue / 3.0));
boolean imof = ((currentValue / 5) == (currentValue / 5.0));
if(imot || imof){
acc += currentValue;
}
currentValue += 1;
}
System.debug(acc);
}
doShit();
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