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import java.util.HashMap; | |
/* | |
The Integer Knapsack Problem (Duplicate Items Permitted). You have n types of | |
items, where the ith item type has an integer size si and a real value vi. You are trying to fill a knapsack of | |
total capacity C with a selection of items of maximum value. You can add multiple items of the same type | |
to the knapsack. | |
s = {3,1,2,4} | |
v = {4,1,3,2} | |
item1: has size 3 and value 4 | |
item2 | |
3 | |
4 | |
bag, capacity c = 7 | |
one way is: | |
put item1 and item 4 in the bag (3+4<=7), the value is 4+2=6 | |
*/ | |
public class IntegerKnapsack { | |
public static int getMaxValue(int[] s, int[] v, int c) { | |
HashMap<Integer, Integer> sm = new HashMap<Integer, Integer>(); | |
for (int i=0; i<s.length; i++) { | |
if (sm.containsKey(v[i]) && sm.get(v[i]) < s[i]) { | |
continue; | |
} | |
sm.put(v[i], s[i]); | |
} | |
Arrays.sort(v); | |
int max = 0; | |
int i = v.length - 1; | |
while (i >= 0 && c > 0) { | |
int si = sm.get(v[i]); | |
if (si > c) { | |
//Use the next lesser element only if the capacity exceeds | |
i--; | |
continue; | |
} | |
max += v[i]; | |
c -= si; | |
} | |
return max; | |
} | |
public static void main(String[] args) { | |
int[] s = {5, 21, 12, 7, 15, 13}; | |
int[] i = {6, 3, 9, 9, 4, 2}; | |
System.out.println(IntegerKnapsack.getMaxValue(s, i, 15)); | |
} | |
} |
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