Generates ten pages of ten Instagram URLs that have a specific tag (in this case 'kitten'.) --- Uses python2.7!

Instakitty.py

'''
Created on Apr 4, 2013
 
@author: andrewjkerr
 
Shout out to kiks for the sweet Python lesson last night!
'''
 
import urllib2
import json
 
# Get dat response from dat API yo
# https://api.instagram.com/v1/tags/{tag-name}/media/recent
 
kittenURL = "https://api.instagram.com/v1/tags/kitten/media/recent?client_id={client_id}"
 
def printKitties(kittenURL):
    kittenResponse = urllib2.urlopen(kittenURL)
    
    # Convert to JSON
    kittenJSON = json.loads(kittenResponse.read())
    
    kittenData = kittenJSON["data"] #list of instagram photos
    
    for kitty in kittenData:
        print(kitty["link"])
        
    kittenNextData = kittenJSON["pagination"]
    kittenNextURL = kittenNextData["next_url"]
    
    return kittenNextURL
    
numPages = 10
count = 0
nextURL = kittenURL
while count <= numPages:
    print "New page: " + str(count) + "**"
    nextURL = printKitties(nextURL)
    count += 1