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andypetrella/access.py

Created July 21, 2018 18:07
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How to reference a scala object in python using Py4j (JavaGateway)
Raw
access.py
# This function takes the fully classified object name, say: <package>.<name>.
# Returns the static object instance on the heap
def ref_scala_object(object_name):
clazz = jvm.java.lang.Class.forName(object_name+"$")
ff = clazz.getDeclaredField("MODULE$")
o = ff.get(None)
return o
Raw
usage.py
scala_none = ref_scala_object("scala.None")
scala_none.getClass().getName() # returns 'scala.None$'
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