Utility for for finding a JavaFX node by it's ID

FXUtils.java

package test;

import javafx.scene.*;
import javafx.scene.control.*;

public class FXUtils {

	/**
	 * Find a {@link Node} within a {@link Parent} by it's ID.
	 * <p>
	 * This might not cover all possible {@link Parent} implementations but it's
	 * a decent crack. {@link Control} implementations all seem to have their
	 * own method of storing children along side the usual
	 * {@link Parent#getChildrenUnmodifiable()} method.
	 * 
	 * @param parent
	 *            The parent of the node you're looking for.
	 * @param id
	 *            The ID of node you're looking for.
	 * @return The {@link Node} with a matching ID or {@code null}.
	 */
	@SuppressWarnings("unchecked")
	static <T> T getChildByID(Parent parent, String id) {
		
		String nodeId = null;
		
		if(parent instanceof TitledPane) {
			TitledPane titledPane = (TitledPane) parent;
			Node content = titledPane.getContent();
			nodeId = content.idProperty().get();
			
			if(nodeId != null && nodeId.equals(id)) {
				return (T) content;
			}
			
			if(content instanceof Parent) {
				T child = getChildByID((Parent) content, id);
				
				if(child != null) {
					return child;
				}
			}
		}
		
		for (Node node : parent.getChildrenUnmodifiable()) {
			nodeId = node.idProperty().get();
			if(nodeId != null && nodeId.equals(id)) {
				return (T) node;
			}
			
			if(node instanceof SplitPane) {
				SplitPane splitPane = (SplitPane) node;
				for (Node itemNode : splitPane.getItems()) {
					nodeId = itemNode.idProperty().get();
					
					if(nodeId != null && nodeId.equals(id)) {
						return (T) itemNode;
					}
					
					if(itemNode instanceof Parent) {
						T child = getChildByID((Parent) itemNode, id);
						
						if(child != null) {
							return child;
						}
					}
				}
			}
			else if(node instanceof Accordion) {
				Accordion accordion = (Accordion) node;
				for (TitledPane titledPane : accordion.getPanes()) {
					nodeId = titledPane.idProperty().get();
					
					if(nodeId != null && nodeId.equals(id)) {
						return (T) titledPane;
					}
					
					T child = getChildByID(titledPane, id);
					
					if(child != null) {
						return child;
					}
				}
			}
			else   if(node instanceof Parent) {
				T child = getChildByID((Parent) node, id);
				
				if(child != null) {
					return child;
				}
			}
		}
		return null;
	}
}

Maybe my article about walking the JavaFX scene graph will be helpful in this context: http://www.kware.net/?p=8

Nice. I am not criticising, but are there any drawbacks in using the below code instead of your utility ?

Node child = parent.lookup("#"+id);