Created
February 5, 2017 17:18
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crude combination solution with dynamic programming
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def factorial(n): | |
if factorial_array[n] > -1: | |
return factorial_array[n] | |
else: | |
factorial_array[n-1] = factorial(n - 1) | |
return n * factorial_array[n-1] | |
def combination(n, k): | |
if k == 0 or n == k: | |
return 1 | |
else: | |
return int(factorial(n) / factorial(k) / factorial(n - k)) | |
a = input().split(' ') | |
if not a[0].isdigit() or len(a) == 1 or not a[1].isdigit(): | |
print('both n and k should be numbers') | |
quit() | |
n, k = int(a[0]), int(a[1]) | |
if n < 0 or k < 0: | |
print('both n and k should be >= 0') | |
quit() | |
factorial_array = [1] | |
factorial_array = factorial_array + [-1] * n #fill list with -1 n times | |
for n2 in range(n + 1): | |
for k2 in range(n2 + 1): | |
print("{0}C{1} = {2}".format(n2, k2, combination(n2, k2)), end=" ") | |
print() |
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