Last active
June 3, 2017 15:05
-
-
Save anil477/05906ad3b2e295c60122b5d2a7651443 to your computer and use it in GitHub Desktop.
Sort a linked list of 0,1 and 2's - count 0, 1 and 2's.
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
// So we create there list, one each for 0, 1 and 2. | |
// The head of each of these point to the 0, 1 and 2, node in the main list given. | |
// while travesing we point head0 to first node with 0, the next of which points to next node with 0 and it goes on. | |
// similarly for 1 and 2. | |
// in the end we add head2 at end of head1. n then add head1 to end of head0. | |
// ignore the crappy naming convention. It's jsut a POC that it can be done this way. GeeksForGeek does not has this solution | |
class Node { | |
int data; | |
Node next; | |
Node(int d) | |
{ | |
data = d; | |
next = null; | |
} | |
} | |
class LinkedList | |
{ | |
Node head; // head of list | |
/* This function prints contents of linked list starting from head */ | |
public void printList() | |
{ | |
Node temp = head; | |
System.out.println( " Print Function: "); | |
while (temp != null) | |
{ | |
System.out.println("Data: " + temp.data); | |
temp = temp.next; | |
} | |
System.out.println(); | |
} | |
public void create() | |
{ | |
Node head0 = null; | |
Node head1 = null; | |
Node head2 = null; | |
Node f = null; | |
Node node0 = null; | |
Node node1 = null; | |
Node node2 = null; | |
Node temp = this.head; | |
while (temp!=null) | |
{ | |
if (temp.data == 0) | |
{ | |
if(head0 == null) | |
{ | |
node0 = new Node(0); | |
head0 = node0; | |
node0.next = null; | |
} | |
else | |
{ | |
node0 = new Node(0); | |
f = head0; | |
while(f.next!=null) | |
{ | |
f = f.next; | |
} | |
f.next = node0; | |
} | |
} | |
else if(temp.data == 1) | |
{ | |
if(head1 == null) | |
{ | |
node1 = new Node(1); | |
head1 = node1; | |
node1.next = null; | |
} | |
else | |
{ | |
node1 = new Node(1); | |
f = head1; | |
while(f.next!=null) | |
{ | |
f = f.next; | |
} | |
f.next = node1; | |
} | |
} | |
else if(temp.data == 2) | |
{ | |
if(head2 == null) | |
{ | |
node2 = new Node(2); | |
head2 = node2; | |
node2.next = null; | |
} | |
else | |
{ | |
node2 = new Node(2); | |
f = head2; | |
while(f.next!=null) | |
{ | |
f = f.next; | |
} | |
f.next = node2; | |
} | |
} | |
temp = temp.next; | |
} | |
Node loop0 = head0; | |
while(loop0.next!=null) | |
{ | |
loop0 = loop0.next; | |
} | |
loop0.next = head1; | |
loop0 = head0; | |
while(loop0.next!=null) | |
{ | |
loop0 = loop0.next; | |
} | |
loop0.next = head2; | |
loop0 = head0; | |
while(loop0!=null) | |
{ | |
System.out.println(loop0.data); | |
loop0 = loop0.next; | |
} | |
} | |
public static void main(String[] args) | |
{ | |
LinkedList llist = new LinkedList(); | |
llist.head = new Node(0); | |
Node second = new Node(2); | |
Node third = new Node(1); | |
Node fourth = new Node(2); | |
Node fifth = new Node(2); | |
llist.head.next = second; | |
second.next = third; | |
third.next = fourth; | |
fourth.next = fifth; | |
llist.printList(); | |
llist.create(); | |
} | |
public void addAtHead(int data) | |
{ | |
Node node = new Node(data); | |
node.next = this.head; | |
this.head = node; | |
} | |
} |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment