Sort an array of integer where the integer are very large and they need to be stored at string.

sortVeryLargeNumber.java

import java.util.*;
import java.util.Comparator;

class CompareData implements Comparator<String> {
 
    @Override
    public int compare(String date1, String date2) {
        if(date1.length() > date2.length()) {
            return 1;
        } 
        else if (date1.length() < date2.length()) {
            return -1;
        } else if (date1.length() == date2.length()) {
          return date1.compareTo(date2);
        }
        return 0;
    }
}

class Test{
    
    public static void main(String[] args){
        
        List<String> list = new ArrayList<String>();
 
        list.add("1234567890123456789012345678901234567890");
        list.add("1234567890123456789012345678901234567899");
        list.add("1234567890123456789012345678901234567896");
        list.add("123456789");
        list.add("123456788");
        
        // System.out.println("Before sorting: " + list);

        Collections.sort(list, new CompareData());

        System.out.println("After sorting: " + list);
    } 
}