Created
November 15, 2017 07:09
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Find the position to insert element in a sorted array
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// Java implementation of iterative Binary Search | |
class BinarySearch | |
{ | |
// Returns index of x if it is present in arr[], else | |
// return -1 | |
int binarySearch(int arr[], int x) | |
{ | |
if(x > arr[arr.length-1]) { | |
return arr.length; | |
} | |
int l = 0, r = arr.length - 1; | |
while (l <= r) | |
{ | |
int m = l + (r-l)/2; | |
// Check if x is present at mid | |
if (arr[m] == x || ( (m == 0 || arr[m-1] < x )) && (m == (arr.length-1) || x < arr[m])) | |
return m; | |
// If x greater, ignore left half | |
if (arr[m] < x) | |
l = m + 1; | |
// If x is smaller, ignore right half | |
else | |
r = m - 1; | |
} | |
// if we reach here, then element was not present | |
return -1; | |
} | |
// Driver method to test above | |
public static void main(String args[]) | |
{ | |
BinarySearch ob = new BinarySearch(); | |
int arr[] = {0, 5, 10, 15, 20}; | |
int n = arr.length; | |
int x = -22; | |
int result = ob.binarySearch(arr, x); | |
if (result == -1) | |
System.out.println("Element not present"); | |
else | |
System.out.println("Element found at index "+result); | |
} | |
} |
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