Skip to content

Instantly share code, notes, and snippets.

@anil477
Created July 10, 2017 18:42
Show Gist options
  • Star 0 You must be signed in to star a gist
  • Fork 0 You must be signed in to fork a gist
  • Save anil477/fafd8f9d7c347d4cd232b459b098d3ce to your computer and use it in GitHub Desktop.
Save anil477/fafd8f9d7c347d4cd232b459b098d3ce to your computer and use it in GitHub Desktop.
LCA In BST
// Recursive Java program to print lca of two nodes
// A binary tree node
class Node
{
int data;
Node left, right;
Node(int item)
{
data = item;
left = right = null;
}
}
class BinaryTree
{
Node root;
/* Function to find LCA of n1 and n2. The function assumes that both
n1 and n2 are present in BST */
Node lca(Node node, int n1, int n2)
{
if (node == null)
return null;
// If both n1 and n2 are smaller than root, then LCA lies in left
if (node.data > n1 && node.data > n2)
return lca(node.left, n1, n2);
// If both n1 and n2 are greater than root, then LCA lies in right
if (node.data < n1 && node.data < n2)
return lca(node.right, n1, n2);
return node;
}
/* Driver program to test lca() */
public static void main(String args[])
{
// Let us construct the BST shown in the above figure
BinaryTree tree = new BinaryTree();
tree.root = new Node(20);
tree.root.left = new Node(8);
tree.root.right = new Node(22);
tree.root.left.left = new Node(4);
tree.root.left.right = new Node(12);
tree.root.left.right.left = new Node(10);
tree.root.left.right.right = new Node(14);
int n1 = 10, n2 = 14;
Node t = tree.lca(tree.root, n1, n2);
System.out.println("LCA of " + n1 + " and " + n2 + " is " + t.data);
n1 = 14;
n2 = 8;
t = tree.lca(tree.root, n1, n2);
System.out.println("LCA of " + n1 + " and " + n2 + " is " + t.data);
n1 = 10;
n2 = 22;
t = tree.lca(tree.root, n1, n2);
System.out.println("LCA of " + n1 + " and " + n2 + " is " + t.data);
}
}
Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment