Created
September 29, 2015 17:14
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#include <iostream> | |
#include <vector> | |
#include <conio.h> | |
#include <stdio.h> | |
#include <cmath> | |
using namespace std; | |
merge(vector<int> arr,vector<int> arr1,vector<int> arr2) | |
{ | |
for(int i = 0;i<arr1.size();) | |
for(int j = 0;j<arr2.size();) | |
for(int k = 0;k<arr.size();k++) | |
{ | |
if(arr1[i]<arr2[j]) | |
{ | |
arr[k]=arr1[i]; | |
i++; | |
} | |
else if(arr1[i]>arr2[j]) | |
{ | |
arr[k]=arr2[j]; | |
j++; | |
} | |
} | |
return arr; | |
} | |
int main() | |
{ | |
int n,m; | |
scanf("%u", &n); | |
m=(n+1)/2; | |
vector<int> arr(n); | |
vector<int> arr1(m+1); | |
vector<int> arr2(m+1); | |
for (int i = 0;i < n;i++) | |
scanf("%u", &arr[i]); | |
//if(n%2==0) | |
for (int t = 0; t < m; t++) | |
{ | |
arr1[t]=arr[t]; | |
} | |
/*else(n%2==1) | |
for (int t = 0; t < (n+1)/2; t++) | |
{ | |
arr1[t]=arr[t]; | |
}*/ | |
for (int i = 0; i < m-1; i++) | |
for (int j = 1; j < m; j++) | |
{ | |
if(arr1[j]<arr1[i]) | |
{ | |
int p=arr1[j]; | |
arr1[j]=arr1[i]; | |
arr1[i]=p; | |
} | |
} | |
for(int z=m;z<(2*m);z++) | |
{ | |
arr2[z]=arr[z]; | |
} | |
for (int i = m; i < (2*m)-1 ; i++) | |
for(int j=m+1;j<(2*m);j++) | |
{ | |
if(arr2[j]<arr2[i]) | |
{ | |
int p=arr2[j]; | |
arr2[j]=arr2[i]; | |
arr2[i]=p; | |
} | |
} | |
cout<<merge(arr,arr1,arr2); | |
for (int j = 0;j < n;j++) | |
printf("%u\n", arr[j]); | |
for (int j = 0;j < m;j++) | |
printf("%u\n", arr1[j]); | |
int d; | |
if (n%2==0) | |
for (int j = m;j < (2*m);j++) | |
printf("%u\n", arr2[j]); | |
else | |
for (int j = m+1;j < (2*m);j++) | |
printf("%u\n", arr2[j]); | |
return 0; | |
} |
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