Water Jug problem. An arithmatic approach

Water Jug Problem.py

#Written by: Anish Mashankar
#Blog: http://techieanish.blogspot.com

#####BEGIN#####
print 'enter capacity of first jug'
x_capacity = input()
print 'enter capacity of second jug'
y_capacity = input()
print 'enter goal capacity'
x_goal = input()
print 'enter where the goal state is'
req_goal = input()
x = 0
y = 0
finish = False

def fill_x():
	print 'fill x'
	global x, x_capacity, y
	x = x_capacity
	print x,y
def empty_y():
	print 'empty y'
	global y,x
	y = 0
	print x,y
def transfer_x_to_y():
	print 'transfer x to y'
	global x_capacity, y_capacity, x, y
	fin=0
	while fin==0:
		x = x-1
		y = y+1
		if (y == y_capacity) or x == 0:
			fin=1
	print x,y
while not finish:
	if x == x_goal or y == x_goal:
		finish = True
	elif x == 0:
		fill_x()
		continue
	elif x > 0 and y != y_capacity:
		transfer_x_to_y()
		continue
	elif x > 0 and y == y_capacity:
		empty_y()
		continue
if req_goal == 1:
	if x != x_goal:
		x == x_goal
	y = 0
if req_goal == 2:
	if y != x_goal:
		y = x_goal
	x = 0
print 'making modifications'
print x,y