clang.log

 error: no matching constructor for initialization of 'use_arg'
        { ::new((void *)__p) _Up(std::forward<_Args>(__args)...); }
                             ^   ~~~~~~~~~~~~~~~~~~~~~~~~~~~
 note: in instantiation of function template specialization '__gnu_cxx::new_allocator<use_arg>::construct<use_arg, int, std::scoped_allocator_adaptor<std::allocator<use_arg>> &>' requested here
        { __a.construct(__p, std::forward<_Args>(__args)...); }
              ^
 note: in instantiation of function template specialization 'std::allocator_traits<std::allocator<use_arg> >::construct<use_arg, int, std::scoped_allocator_adaptor<std::allocator<use_arg>> &>' requested here
          _O_traits::construct(__outermost(*this), __p,
                     ^
 note: in instantiation of function template specialization 'std::scoped_allocator_adaptor<std::allocator<use_arg>>::_M_construct<use_arg, int>' requested here
          _M_construct(__use_tag, __p, std::forward<_Args>(__args)...);
          ^
 note: in instantiation of function template specialization 'std::scoped_allocator_adaptor<std::allocator<use_arg>>::construct<use_arg, int>' requested here
    sa.construct(p, 4);
       ^
 note: candidate constructor template not viable: requires 3 arguments, but 2 were provided
    use_arg(std::allocator_arg_t, Alloc &, int i)
    ^
 note: candidate constructor (the implicit copy constructor) not viable: requires 1 argument, but 2 were provided
struct use_arg {
       ^
 note: candidate constructor (the implicit move constructor) not viable: requires 1 argument, but 2 were provided
1 error generated.

gcc.log

In instantiation of ‘void __gnu_cxx::new_allocator<_Tp>::construct(_Up*, _Args&& ...) [with _Up = use_arg; _Args = {int, std::scoped_allocator_adaptor<std::allocator<use_arg> >&}; _Tp = use_arg]’:
   
   required from ‘static std::_Require<typename std::allocator_traits<_Alloc>::__construct_helper<_Tp, _Args>::type> std::allocator_traits<_Alloc>::_S_construct(_Alloc&, _Tp*, _Args&& ...) [with _Tp = use_arg; _Args = {int, std::scoped_allocator_adaptor<std::allocator<use_arg> >&}; _Alloc = std::allocator<use_arg>; std::_Require<typename std::allocator_traits<_Alloc>::__construct_helper<_Tp, _Args>::type> = void]’
   
   required from ‘static decltype (_S_construct(__a, __p, (forward<_Args>)(std::allocator_traits::construct::__args)...)) std::allocator_traits<_Alloc>::construct(_Alloc&, _Tp*, _Args&& ...) [with _Tp = use_arg; _Args = {int, std::scoped_allocator_adaptor<std::allocator<use_arg> >&}; _Alloc = std::allocator<use_arg>; decltype (_S_construct(__a, __p, (forward<_Args>)(std::allocator_traits::construct::__args)...)) = <type error>]’

   required from ‘void std::scoped_allocator_adaptor<_OuterAlloc, _InnerAllocs>::_M_construct(std::scoped_allocator_adaptor<_OuterAlloc, _InnerAllocs>::__uses_alloc2_, _Tp*, _Args&& ...) [with _Tp = use_arg; _Args = {int}; _OuterAlloc = std::allocator<use_arg>; _InnerAllocs = {}; std::scoped_allocator_adaptor<_OuterAlloc, _InnerAllocs>::__uses_alloc2_ = std::__uses_alloc2<std::scoped_allocator_adaptor<std::allocator<use_arg> > >; typename std::__inner_type_impl<_OuterAlloc, _InnerAllocs ...>::__type = std::scoped_allocator_adaptor<std::allocator<use_arg> >]’
   
   required from ‘void std::scoped_allocator_adaptor<_OuterAlloc, _InnerAllocs>::construct(_Tp*, _Args&& ...) [with _Tp = use_arg; _Args = {int}; _OuterAlloc = std::allocator<use_arg>; _InnerAllocs = {}]’
 
 错误：对‘use_arg::use_arg(int, std::scoped_allocator_adaptor<std::allocator<use_arg> >&)’的调用没有匹配的函数
  { ::new((void *)__p) _Up(std::forward<_Args>(__args)...); }
    ^
 
 附注：candidate: template<class Alloc> use_arg::use_arg(std::allocator_arg_t, Alloc&, int)
     use_arg(std::allocator_arg_t, Alloc &, int i)
     ^
 
 附注：  template argument deduction/substitution failed:
 
 附注：  cannot convert ‘std::forward<int>((* & __args#0))’ (type ‘int’) to type ‘std::allocator_arg_t’
  { ::new((void *)__p) _Up(std::forward<_Args>(__args)...); }
    ^
 附注：candidate: constexpr use_arg::use_arg(const use_arg&)
 struct use_arg {
        ^
 
 附注： 备选需要 1 实参，但提供了 2 个
 
 附注：candidate: constexpr use_arg::use_arg(use_arg&&)
 
 附注： 备选需要 1 实参，但提供了 2 个