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Created March 22, 2013 19:59
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Pig Latin Translator (Learned through Codecademy.com's Python Track). There must be a shorter way to determine a vowel within a word.
# Defining main variables for translator
pyg = 'ay'
original = raw_input('Enter a word:')
word = original.lower()
first = word [0]
#Beginning of if/else statements
if len(original) > 0 and original.isalpha():
if first == "a" or first == "e" or first == "i" or first == "o" or first == "u":
new_word = word+pyg
print new_word
else:
new_word = word[1:]+first+pyg
print new_word
else:
print 'empty'
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