gistfile1.txt

int main(){
	//init vars
	string fileLocation;
	ifstream file;
	string line;
	char c;
	char frequent;
	int k;
	int i;
	char letters[26]={'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 
		'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'};

	char lowerLetters[26]={'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 
		'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z'};
	//Ask the user for the file location 
	//and opening the contents of the file.
	cout << "Enter the location of the file you'd like to decipher: ";
	cin >>fileLocation;

	file.open(fileLocation);

	if(!file){
		cout <<"Error opening the file location" <<endl;
		getchar();
		return 0;
	}

	frequent = frequencyCount(fileLocation); //This is where our function counts for the most frequent letter.

	
	
	for(int i=0;i<26;i++){
		if(letters[i]==frequent){
			k = i-4; //Since frequent is what we are assuming to be 'E' when decyphered,
					//when letters[i] also is equal to 'E', i-5 will give us the shift for the code.
			
				}
	}
	while(file.get(c)){  //I put this here just to output the txt file for now
		cout <<char(c);
	}
	

	getchar();
	getchar();
	return 0;
}


char frequencyCount(string fileLocation){ //This function will return the most frequently used letter,
	char c;								  //which we are assuming to be an 'E' when decyphered.
	int total[26]={0};
	int frequency = 0;
	char frequent;
	ifstream file;

	file.open(fileLocation);

	while(file.get(c)){
		if (isalpha(c)){
			c=toupper(c);
			int index = c - 'A';
			total[index]++;
			
			if(total[index] > frequency){
				frequency = total[index];
				frequent = char(index + 'A');
			}
		}
	}

	 
	return frequent;
	
 
}