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Created September 23, 2014 05:08
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test
# ##### BEGIN GPL LICENSE BLOCK #####
#
# This program is free software; you can redistribute it and/or
# modify it under the terms of the GNU General Public License
# as published by the Free Software Foundation; either version 2
# of the License, or (at your option) any later version.
#
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU General Public License for more details.
#
# You should have received a copy of the GNU General Public License
# along with this program; if not, write to the Free Software Foundation,
# Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301, USA.
#
# ##### END GPL LICENSE BLOCK #####
import bisect
import numpy as np
# spline function modifed from
# from looptools 4.5.2 done by Bart Crouch
# calculates natural cubic splines through all given knots
def cubic_spline(locs, tknots):
knots = list(range(len(locs)))
n = len(knots)
if n < 2:
return False
x = tknots[:]
result = []
for j in range(3):
a = []
for i in locs:
a.append(i[j])
h = []
for i in range(n-1):
if x[i+1] - x[i] == 0:
h.append(1e-8)
else:
h.append(x[i+1] - x[i])
q = [False]
for i in range(1, n-1):
q.append(3/h[i]*(a[i+1]-a[i]) - 3/h[i-1]*(a[i]-a[i-1]))
l = [1.0]
u = [0.0]
z = [0.0]
for i in range(1, n-1):
l.append(2*(x[i+1]-x[i-1]) - h[i-1]*u[i-1])
if l[i] == 0:
l[i] = 1e-8
u.append(h[i] / l[i])
z.append((q[i] - h[i-1] * z[i-1]) / l[i])
l.append(1.0)
z.append(0.0)
b = [False for i in range(n-1)]
c = [False for i in range(n)]
d = [False for i in range(n-1)]
c[n-1] = 0.0
for i in range(n-2, -1, -1):
c[i] = z[i] - u[i]*c[i+1]
b[i] = (a[i+1]-a[i])/h[i] - h[i]*(c[i+1]+2*c[i])/3
d[i] = (c[i+1]-c[i]) / (3*h[i])
for i in range(n-1):
result.append([a[i], b[i], c[i], d[i], x[i]])
splines = []
for i in range(len(knots)-1):
splines.append([result[i], result[i+n-1], result[i+(n-1)*2]])
return(splines)
def eval_spline(splines, tknots, t_in):
out = []
for t in t_in:
n = bisect.bisect(tknots, t, lo=0, hi=len(tknots))-1
if n > len(splines)-1:
n = len(splines)-1
if n < 0:
n = 0
pt = []
for i in range(3):
ax, bx, cx, dx, tx = splines[n][i]
x = ax + bx*(t-tx) + cx*(t-tx)**2 + dx*(t-tx)**3
pt.append(x)
out.append(pt)
return out
def interpolation(v, t_in, mode='SPL'):
'''
input
v : list, vectors to interpolate
t_in : list, interpolation points [0.0 <= t_in <= 1.0]
modes : string,
('SPL', 'Cubic', "Cubic Spline"),
('LIN', 'Linear', "Linear Interpolation")
output
_ : list, interpolated coordinates
'''
pts = np.array(v).T
tmp = np.apply_along_axis(np.linalg.norm, 0, pts[:, :-1]-pts[:, 1:])
t = np.insert(tmp, 0, 0).cumsum()
t = t/t[-1]
t_corr = [min(1, max(t_c, 0)) for t_c in t_in]
# this should also be numpy
if mode == 'LIN':
out = [np.interp(t_corr, t, pts[i]) for i in range(3)]
return list(zip(*out))
else: # SPL
spl = cubic_spline(v, t)
return eval_spline(spl, t, t_corr)
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