Created
June 13, 2019 22:13
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c++ equivalent of generic type constraints
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// c++11, c++14, c++17 | |
#include <iostream> | |
#include <type_traits> | |
using namespace std; | |
class BaseClass { }; | |
class OtherClass { }; | |
class DerivedClass : BaseClass {}; | |
template <typename T> | |
typename enable_if_t<is_base_of_v<BaseClass, T>, bool> hasBaseClass(const T& t) | |
{ | |
return true; | |
} | |
template <typename T> | |
typename enable_if_t<!is_base_of_v<BaseClass, T>, bool> hasBaseClass(const T& t) | |
{ | |
return false; | |
} | |
template <typename T, | |
typename = enable_if_t<is_base_of_v<BaseClass, T>>> | |
auto only_defined_for_derived(const T& t) | |
{ | |
return 42; | |
} | |
int main() | |
{ | |
auto baseClass = BaseClass{}; | |
auto otherClass = OtherClass{}; | |
auto derivedClass = DerivedClass{}; | |
cout << "baseClass: " << hasBaseClass(baseClass) << endl; | |
cout << "otherClass: " << hasBaseClass(otherClass) << endl; | |
cout << "derivedClass: " << hasBaseClass(derivedClass) << endl; | |
auto a = only_defined_for_derived(baseClass); | |
//auto b = only_defined_for_derived(otherClass); // compiler error, as expected | |
auto c = only_defined_for_derived(derivedClass); | |
return 0; | |
} | |
/* | |
Outputs: | |
baseClass: 1 | |
otherClass: 0 | |
derivedClass: 1 | |
*/ |
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