Problem solved on Top Coders.(14.2.500)

#King_Of_Kings.groovy

//map for managing the conversion from roman to no's
def map =[I:1,II:2,III:3,IV:4,V:5,VI:6,VII:7,VIII:8,IX:9,X:10,XI:11]
//map for managing the conversion from no to romans
def map1 = ['1':"I",'2':"II",'3':"III",'4':"IV",'5':"V",'6':"VI",'7':"VII",'8':"VIII",'9':"IX",'10':"X",'11':"XI"]
//temp variables
ans = []
res = []
//final result
res1 = []
//for managing the flow of algorithm
bool = true
//yes, its input
def input = ["La IV","L IV","La IV","La I","L I"]
//main method
//map paramter is used to select any one of map either map, or map1
//see above 
def method(def map,def input) {
	def a = input
	def temp = a.split(' ')
	if(bool == true)
		f= map.get(temp[1])
	else
		f=map.get(temp[1])
	//temp having [asads,2], need to delete 2 and put II!
	//temp is also used for converting [asdasd, II] to delete II and put 2!
	//so basically temp[1] gets deleted that is, either no or romans
	//and at last to the ans, the code adds the required thing
	ans = temp - temp[1] as List
	//adds either nos/romans based on vaule of f, which in turn based on
	//bool value
	ans << " $f"
	//managing concurrent modification! so this if is needed here! :(
	if(bool == true)
		//for initial sort
		res << ans.join()
	else
		//for final answer format
		res1 << ans.join()
}
//do the sort normally
if(bool ==true)
	input.each { method(map,it) }
//do the formatting work...
//change to bool and call the method again
bool =false
if(bool == false)
{
	//this is imp.. because making ans an empty map again as 
	// this list is used in my method.
	//since ans has value from calling method on bool == true
	// I need to delete it!, for tidy work..
	ans = []
	//since I'm formatting res I need to sort it before..
	//because thats where I have sorted in this format [a 1, a 2]
	res.sort()
	//calling the below method coverts that into [a I,a II]
	res.each { method(map1,it) }
}
println res1