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February 4, 2012 15:46
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Insertion Sort In Groovy
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a = [2,34,4,123,45,56,3,56,67,87,21,45,56,67,22,4234,4234,2342,1,34,546,67,677,343,4,41,32,456,1341,13,454,234,453,565,5,524,234,234,5456,567,673,245,567,78,78,324,56576,782,435,676,873,2,345,6767,7,3463,3,6767673,34534,2,345,656,3,5652,1,34345,3453545,35345356,66,7883345,676787,8988] | |
b = a | |
long startTime = System.currentTimeMillis(); | |
(1..(a.size()-2)).each { out -> | |
def temp = a.getAt(out) | |
def index = out | |
while(index>0 && a.getAt(index-1) >= temp) | |
{ | |
value = a.getAt(index-1) | |
a.putAt(index,value) | |
--index | |
} | |
a.putAt(index,temp) | |
} | |
long endTime = System.currentTimeMillis(); | |
println "The insertion sort have taken ${endTime-startTime} seconds to finish sorting for ${a.size()} elements \n \n" | |
println a | |
//test cases... these are passing!! Yipeee :D | |
assert b.sort() == a | |
assert b.size() == a.size() |
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IMO 4 line for:
(1..(a.size()-1)).each { out ->
the last element is not triggered