https://clojure.org/news/2021/03/18/apis-serving-people-and-programs
https://www.youtube.com/watch?v=pd8kWJVDQD4
https://twitter.com/yogthos/status/1373270067736162305
https://yyhh.org/blog/2021/03/how-much-can-a-clojure-developer-do-alone/
Notes
- Use the REPL
- Get a teacher
- Clojure was design for small teams
- Composable, readability, abstraction
Sept 30 - Oct 2, 2021
https://www.learn-clojurescript.com/
String difference
You are given two strings, a and b. We consider each letter to be unique, meaning duplicates are significant. Write a function that returns the count of letters in b which do not occur in a.
Examples
(strdiff "abc" "") ;=> {} ;; no characters in b don't occur in a
(strdiff "abc" "abc") ;=> {} ;; ditto
(strdiff "" "abc") ;=> {\a 1 \b 1 \c 1}
(strdiff "axx" "abcc") ;=> {\b 1 \c 2}
(strdiff "xxxx" "xxxxxx") ;=> {\a 2} ;; two x's in b that don't occur in aThanks to this site for the challenge idea where it is considered Hard in Python. The problem has been modified from the original.
From PurelyFunctional.tv Newsletter 419
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