Created
August 18, 2012 15:01
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invertbit
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package com.adp.invertbit; | |
public class InvertBit { | |
public char invertBit(char inputChar, int position, int noOfPositions) { | |
//Write your code here | |
int rem = (char)inputChar; //the reminder in each stage of division | |
byte[] charArr = new byte[8]; //storing the bit representation | |
int i = 7; | |
//conversion of char(int) to array of bin numbers | |
while(!(rem == 0) && (i !=0)) { | |
if(rem % 2 == 0) { | |
charArr[i] = 0; | |
} | |
else { | |
charArr[i] = 1; | |
} | |
rem = rem/2; | |
--i; | |
} | |
for(i = 0; i<=7; i++){ | |
System.out.println(charArr[i]);} | |
//inverting the bits | |
for(i = position-1; i < (position+noOfPositions-1); i++) { | |
if (charArr[i] == 0) { | |
charArr[i] = 1; | |
} | |
else{ | |
charArr[i] = 0; | |
} | |
} | |
System.out.println("invert"); | |
for(i = 0; i<=7; i++){ | |
System.out.println(charArr[i]);} | |
// converting back to int | |
int resultInt = 0; | |
i = 0; | |
int j; | |
for(i = 0, j = 7; i < 7; i++, j--){ | |
resultInt += charArr[j] * java.lang.Math.pow(2,i); | |
} | |
char resultChar = (char) resultInt; | |
return resultChar; | |
} | |
public static void main(String ar[]) { | |
char x = 'J'; | |
int p = 3, n = 5; | |
char newChar =new InvertBit().invertBit(x, p, n); | |
System.out.println("\n\n New Character :"+ newChar); | |
} | |
} | |
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