Created
July 14, 2019 23:30
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# 617 Maximum Average Subarray | |
class Solution: | |
""" | |
@param nums: an array with positive and negative numbers | |
@param k: an integer | |
@return: the maximum average | |
""" | |
def maxAverage(self, nums, k): | |
# write your code here | |
high = 1 << 32 | |
low = -high | |
EPS = 1e-5 | |
while low + EPS < high: | |
mid = (low + high) / 2 | |
# print(low, mid, high) | |
# If the average is possible | |
if self.check(nums, k, mid): | |
low = mid | |
else: | |
high = mid | |
return low | |
# check if there is a subarray that has average greater or equal to avg | |
def check(self, nums, k, avg): | |
arr = [0] + [n - avg for n in nums] | |
for i in range(1, len(arr)): | |
arr[i] += arr[i - 1] | |
# print(arr) | |
low = 0 | |
high = k | |
lowmin = arr[0] | |
while high < len(arr): | |
lowmin = min(arr[low], lowmin) | |
if arr[high] >= lowmin: | |
return True | |
low += 1 | |
high += 1 | |
return False |
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