Created
November 15, 2012 05:41
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Execute a logger as a subprocess and exec, leaving only the two child processes without using bash 4.0
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| #!/bin/bash | |
| tmp=/tmp/$$.pipe | |
| mkfifo $tmp | |
| logger -p local6.debug < $tmp & | |
| exec > $tmp | |
| rm $tmp | |
| exec $@ |
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oh, awesome. Nice little hack... I hadn't been aware of the behavior of exec without arguments