Created
December 21, 2014 16:16
-
-
Save arjunrao87/01b1d176e733455ea7a9 to your computer and use it in GitHub Desktop.
Given an unsorted array of n integers, find a pair of integers whose sum = k
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
//Method 1 : Time = O(n), Space = O(1) | |
public List<Pair<Integer, Integer>> getPairsOfIntegers( int[] numbers, int sum ){ | |
List<Pair<Integer,Integer>> results = new ArrayList<>(); | |
int[] sortedNumbers = doRadixSort( numbers ); | |
int left = 0; | |
int right = sortedNumbers.length - 1; | |
while( left < right ){ | |
int currentSum = sortedNumbers[ left ] + sortedNumbers[ right ]; | |
if ( currentSum == sum ){ | |
results.add( new Pair<Integer,Integer>( sortedNumbers[ left ], sortedNumbers[ right ] ); | |
} else if ( currentSum < sum ){ | |
left++; | |
} else if ( currentSum > sum ){ | |
right --; | |
} | |
} | |
return results; | |
} | |
//Method 2 : Time = O(n), Space = O(n) | |
public List<Pair<Integer, Integer>> PairOfIntegers2( int[] numbers, int sum ){ | |
List<Pair<Integer,Integer>> results = new ArrayList<>(); | |
Map<Integer, Integer> map = new HashMap<>(); | |
for( int i = 0; i< numbers.length; i++ ){ | |
int current = numbers[i]; | |
Integer difference = sum - current; | |
if( map.containsKey( current ){ | |
results.add( new Pair<Integer, Integer>( current, difference ); | |
} else{ | |
map.put( difference, current ); | |
} | |
} | |
return results; | |
} |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment