practice using nested data structures with each

enumerable.rb

# create a new hash that has this structure
# {
#  "A" => "a"
#	"B" => "b"
#	...
#	"Z" => "z"
#}

#using a single each loop
#know that you can do (A..Z) and (a..z)

# make a hash that will store our final values
# create an each statement to iterate over the range A..Z

#alphabet = {}

#('A'..'Z').each do |letter|
#	alphabet[letter] = letter.downcase
#end

#puts alphabet

# now make it so that it prints 2 letters
# e.g "A" => "aa"
#alphabet = {}

#('A'..'Z').each do |letter|
#	alphabet[letter] = letter.downcase * 2
#end

#puts alphabet

#now make a hash that looks like this
# "A" => ['a']

#alphabet = {}

#('A'..'Z').each do |letter|
#	alphabet[letter] = [letter.downcase]
#end
#
#puts alphabet

# now make a hash that looks like this
# "A" => ['a', 'a']

#alphabet = {}

#('A'..'Z').each do |letter|
#	alphabet[letter] = [letter.downcase, letter.downcase]
#end

#puts alphabet

#now do the same thing, but only say letter.downcase once

#alphabet = {}

#('A'..'Z').each do |letter|
#	alphabet[letter] = []
#	2.times do
#		alphabet[letter].push(letter.downcase)
#	end
#end

#puts alphabet

# now make a hash where it only puts the letter if the letter is the letter O

#alphabet = {}

#('A'..'Z').each do |letter|
#	alphabet[letter] = []
#	if letter == 'O'
#		alphabet[letter].push(letter.downcase)
#	end
#end

#puts alphabet

## now make a hash that only pushs if the letter is part of the the special letters array

#special_letters = ['a','l','e','x']
#alphabet = {}

#('A'..'Z').each do |letter|
#	alphabet[letter] = []
#	if special_letters.include?(letter.downcase)
#		alphabet[letter].push(letter.downcase)
#	end
#end

#puts alphabet

#make a hash that only add the lowercase letter if the letter is in the name

#name = "alex"
#alphabet = {}
#
#('A'..'Z').each do |letter|
#	alphabet[letter] = []
#	if (name.split('')).include?(letter.downcase)
#		alphabet[letter].push(letter.downcase)
#	end
#end

#puts alphabet

# make a hash that looks like this
# "A" => {"a"=>"a"}

#name = "alex"
#alphabet = {}
#
#('A'..'Z').each do |letter|
#	alphabet[letter] = {}
#	alphabet[letter][letter.downcase] = letter.downcase 
#end
#
#puts alphabet

# now make a hash that only adds the key value pair if the letter is in name
# "A" => {"a"=>"a"}, "B" => {} ... "E" => {"e"=>"e"}..

#name = "alex"
#alphabet = {}

#('A'..'Z').each do |letter|
#	alphabet[letter] = {}
#	if name.split('').include?(letter.downcase)
#		alphabet[letter][letter.downcase] = letter.downcase 
#	end
#end

#puts alphabet

# now make an array that gives a value to the nested key only if it is in name, give everything else a 0
# e.g. "A" => {"a" => "a"}, "B" => {"b" => 0}

#name = "alex"
#alphabet = {}

#('A'..'Z').each do |letter|
#	alphabet[letter] = {}
#	if name.split('').include?(letter.downcase)
#		alphabet[letter][letter.downcase] = letter.downcase 
#	end
#end

#puts alphabet

# now make an array that assign a 1 as the value to the nested key if the letter appears in name, otherwise give a 0
#e.g. "A" => {"a" => 1}, "B" => {"b" => 0}

#name = "alex"
#alphabet = {}

#('A'..'Z').each do |letter|
#	alphabet[letter] = {}
#	if name.split('').include?(letter.downcase)
#		alphabet[letter][letter.downcase] = 1
#	else
#		alphabet[letter][letter.downcase] = 0
#	end
#end

#now assign the nested letter a count that reflects how many times that letter appears in the name

name = "williams"
alphabet = {}

('A'..'Z').each do |letter1|
	alphabet[letter1] = {}
	alphabet[letter1][letter1.downcase] = 0
	name.split('').each do |letter2|
		if letter1.downcase == letter2
			alphabet[letter1][letter1.downcase] += 1
		end
	end
end

puts alphabet