Given an array of letters, find word(s) of the same length that you can spell with those letters.

word.py

#!/usr/bin/env python3
words = []
letters = ['a', 'r', 'v', 'b', 'i', 't', 'o']
letters.sort()

# This is the correct path for OSX
f = open('/usr/share/dict/words')

print(f"letters: {letters}")

for line in f:
	if len(line.strip()) == len(letters):
		words.append(line.strip())

for index in range(0, len(words)):
	word_letters = []
	for l in words[index].lower():
		word_letters.append(l)
	word_letters.sort()
	if letters == word_letters:
		print(words[index])