Cassidoo 8.4.23

solution.py

""" 8.3.2023"""
"""
[Cassidoo] Given two strings s and t, return true if t is an anagram of s, and false otherwise. Try this 
in a language you're not comfortable with!"""


def anagram(string1, string2):
    def dict_maker(string):
        dict = {}
        for char in string:
            if char not in dict:
                dict[char] = 0
            dict[char] += 1
        sorted_dict = {key: value for key, value in sorted(dict.items())}
        return sorted_dict

    dict1, dict2 = dict_maker(string1), dict_maker(string2)
    if dict1 == dict2:
        return True
    else:
        return False

print(anagram("noslia", "alison"))