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April 19, 2014 16:20
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ACM-ICPC 4660 - A+B
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//This program is for ACM-ICPC 4660 - A+B | |
//Problem link: https://icpcarchive.ecs.baylor.edu/index.php?option=com_onlinejudge&Itemid=8&category=29&page=show_problem&problem=2661 | |
#include<stdio.h> | |
#include<string.h> | |
using namespace std; | |
int changeBase(int n, int base) | |
{ | |
int len, sum = 0, tmp; | |
char num[6]; | |
sprintf(num, "%d", n);//save n in char array (num) | |
len = strlen(num); | |
for(int i = 0; i < len-1; i++) | |
{ | |
tmp = (num[i] - '0'); | |
sum += tmp; | |
sum *= base; | |
} | |
sum = sum + (num[len-1] - '0'); | |
return sum; | |
} | |
int findBase(int n) | |
{ | |
int Min = 1; | |
while(n != 0) | |
{ | |
int tmp = n % 10; | |
if(tmp > Min) | |
Min = tmp; | |
n = n / 10; | |
} | |
return Min + 1; | |
} | |
int main() | |
{ | |
int n, a, b; | |
scanf("%d", &n); | |
while(n--) | |
{ | |
scanf("%d %d", &a, &b); | |
//printf("%d %d\n", findBase(a), findBase(b)); | |
printf("%d\n", changeBase(a, findBase(a)) + changeBase(b, findBase(b)) ); | |
} | |
return 0; | |
} |
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