openai_test_prompt.txt

Create a Python3 function to determine if two strings are close 

Two strings are considered close if you can attain one from the other using the following operations:

    Operation 1: Swap any two existing characters.
        For example, abcde -> aecdb
    Operation 2: Transform every occurrence of one existing character into another existing character, and do the same with the other character.
        For example, aacabb -> bbcbaa (all a's turn into b's, and all b's turn into a's)
                                    "cabbba" -> "abbccc"

Given two strings, word1 and word2, return true if word1 and word2 are close, and false otherwise.
You can use the operations on either string as many times as necessary.

class Solution:
    def closeStrings(self, word1: str, word2: str) -> bool:
        def close_strings(string1, string2):

openai_test_result.txt

class Solution:
    def closeStrings(self, word1: str, word2: str) -> bool:
        def close_strings(string1, string2):
            if len(string1) != len(string2):
                return False
            else:
                map1 = dict()
                map2 = dict()
                for char in string1:
                    if char not in map1:
                        map1[char] = 1
                    else:
                        map1[char] += 1
                for char in string2:
                    if char not in map2:
                        map2[char] = 1
                    else:
                        map2[char] += 1
                if sorted(map1.keys()) == sorted(map2.keys()):
                    return True
                else:
                    return False
        # Operation 1: Swap any two existing characters
        word1_swap = [char for char in word1]
        for i in range(len(word1_swap)):
            for j in range(i):
                temp = word1_swap[i]
                word1_swap[i] = word1_swap[j]
                word1_swap[j] = temp
                if close_strings(''.join(word1_swap), word2):
                    return True
                # Revert back
                temp = word1_swap[i]
                word1_swap[i] = word1_swap[j]
                word1_swap[j] = temp
        # Operation 2: Transform every occurrence of one existing character into another existing character, and do the same with the other character
        for i in range(len(word1)):
            for j in range(i):
                word1_transform = [char for char in word1]
                word1_transform[i] = word1[j]
                word1_transform[j] = word1[i]
                if close_strings(''.join(word1_transform), word2):
                    return True
        return False