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list intersection
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//a: how would you compute intersection of two lists? | |
//b: I'd use set intersection, but if literally a list, I'd sort then merge: | |
let intersection a b = | |
let rec intersection' a b = | |
match a,b with | |
| _,[] -> [] | |
| [],_ -> [] | |
| x::a',y::b' when x=y -> x::intersection' a' b' | |
| x::a',y::_ when x<y -> intersection' a' b | |
| x::_,y::b' when x>y -> intersection' a b' | |
intersection' (List.sort a) (List.sort b) | |
[ | |
intersection [] [] = [] | |
intersection ['a'] ['a'] = ['a'] | |
intersection ['a'] ['b'] = [] | |
intersection ['a';'b'] ['a';'b'] = ['a';'b'] | |
intersection ['a';'c'] ['c'] = ['c'] | |
intersection ['c'] ['a';'c'] = ['c'] | |
intersection ['b'] [] = [] | |
intersection [] ['b'] = [] | |
intersection ['a';'b';'c'] ['a'] = ['a'] | |
intersection ['a'] ['a';'b';'c'] = ['a'] | |
intersection ['a';'b'] ['b';'a'] = ['a';'b'] | |
intersection ['a'..'d'] ['b'..'g'] = ['b'..'d'] | |
] |
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