sudoku: to get input and convert into array of numbers..

convert-input.c

#include <stdio.h>
#include <stdlib.h>

int length(char *str)
{
    int i;
    i = 0;
    while (str[i])
        ++i;
    return (i);
}

// check if a cell contains a number?

char check_number(char c)
{
    return((('0' <= c) && (c <= '9')) ? c : '0');
}

// inside solve..

// put into array
void solve (char **str)
{
    //char **array[9][9] = malloc(81 * sizeof(char));
    char array[9][9];
    int i;
    int j;

    i = 0;
    while (i < 9)
    {
        j = 0;
        while (j < 9)
        {
            array[i][j] = check_number(str[i][j]);
            ++j;
        }
        ++i;
    }
}


// main

int main(int argrc, char **argrv)
{
    if (argrc != 10)
    {
        printf("Error\n");
    }
    else
    {
        int i;
        int l;
        i = 1;
        l = 0;
        while (i < argrc)
        {
            l = l + length(argrv[i]);
            ++i;
        }
        if (l != 81)
            printf("Error\n");
        else
        {
            char **array[9][9];
            solve(argrv);
    }
    return (0);
    }
}