sudoku: take input and print the matrix

convert-input.c

#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>

void ft_putchar(char c)
{
	write(1, &c, 1);
}

int length(char *str)
{
	int i;
	i = 0;
	while (str[i])
		++i;
	return (i);
}

// check if a cell contains a number? if yes, return the number, if no, return 0
char check_number(char c)
{
	return((('0' <= c) && (c <= '9')) ? (c - '0') : 0);
}

// put a string ".....9..." into an array (which is supposed to be a line)

void put_in_array (int i, char *str, char **array)
{
	int j;

    j = 0;
	while (j < 9)
	{
		array[i][j] = check_number(str[j]);
		++j;
	}
}


// print the array line by line
void    print_array(char **arr)
{
    int x;
    int y;

    y = 0;
    while (y < 9)
    {
        x = 0;
        while (x < 9)
        {
            ft_putchar(arr[y][x] + '0');
            if (x < 8)
                ft_putchar(' ');
            x++;
        }
		ft_putchar('\n');
        y++;
    }
}

// convert input into a nested array, print the matrix
void convert_input(int argrc, char **argrv)
{
	int i;

	char **array;
	array = (char**)malloc(9 * sizeof(char*));

	i = 1;
	while (i < argrc)
	{
		array[(i - 1)] = malloc(9 * sizeof(char));
		put_in_array((i - 1), argrv[i], array);
		++i;
	}
	print_array(array);
}

// main

int main(int argrc, char **argrv)
{
	if (argrc != 10)
	{
		printf("Error\n");
	}
	else
	{
		int i;
		int l;
		i = 1;
		l = 0;
		while (i < argrc)
		{
			l = l + length(argrv[i]);
			++i;
		}
		if (l != 81)
			printf("Error\n");
		else
			convert_input(argrc, argrv);
		return (0);
	}
}