Created
February 12, 2014 16:19
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Combination Sum LeetCode
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public class Solution { | |
public ArrayList<ArrayList<Integer>> combinationSum(int[] candidates, int target) { | |
if(candidates == null) | |
return null; | |
ArrayList<ArrayList<Integer>> result = new ArrayList<ArrayList<Integer>>(); | |
ArrayList<Integer> temp = new ArrayList<Integer>(); | |
if(target <= 0) | |
return result; | |
Arrays.sort(candidates); | |
//currentSum and position are all 0 | |
dfsWorker(candidates, target, result, temp, 0, 0); | |
return result; | |
} | |
public void dfsWorker(int[] candidates, int target, ArrayList<ArrayList<Integer>> result, ArrayList<Integer> temp, int currentSum, int position){ | |
//currentSum reachs target, add the current sequence to result | |
if(currentSum == target){ | |
result.add(new ArrayList<Integer>(temp)); | |
return; | |
} | |
if(currentSum > target) | |
return; | |
for(int i = position;i<candidates.length;i++){ | |
//only no greater than target element will be considered | |
if(candidates[i] <= target){ | |
temp.add(candidates[i]); | |
//since same number can be used more than once, the position is still "i" in arguments | |
dfsWorker(candidates, target, result, temp, candidates[i]+currentSum, i); | |
temp.remove(temp.size()-1); | |
//skip duplicate elements | |
while(i < candidates.length - 1 && candidates[i] == candidates[i+1]) | |
i++; | |
} | |
} | |
} | |
} |
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