Created
April 28, 2017 08:18
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#include <map> | |
#include <set> | |
#include <list> | |
#include <cmath> | |
#include <ctime> | |
#include <deque> | |
#include <queue> | |
#include <stack> | |
#include <string> | |
#include <bitset> | |
#include <cstdio> | |
#include <limits> | |
#include <vector> | |
#include <climits> | |
#include <cstring> | |
#include <cstdlib> | |
#include <fstream> | |
#include <numeric> | |
#include <sstream> | |
#include <iostream> | |
#include <algorithm> | |
#include <unordered_map> | |
#include <unordered_set> | |
#include <tuple> | |
using namespace std; | |
class DFSCountEasy { | |
public: | |
long long f[9000][13]; | |
bool visit[13]; | |
void dfs(vector<string>& G, int k) { | |
visit[k] = 1; | |
for (int i=0; i<G.size(); i++) { | |
if (G[k][i] == 'Y' && !visit[i]) | |
dfs(G, i); | |
} | |
} | |
long long solve(vector<string>& G, int mask, int cur) { | |
if (f[mask][cur] == -1) { | |
f[mask][cur] = 0; | |
for (int i=0; i<G.size(); i++) { | |
if (G[cur][i] == 'N' || (mask & (1<<i))) continue; | |
memset(visit, 0, sizeof(visit)); | |
for (int j=0; j<G.size(); j++) { | |
if (mask & (1<<j)) visit[cur] = 1; | |
} | |
dfs(G, i); | |
int nmask = 0; | |
for (int j=0; j<G.size(); j++) { | |
if (visit[j]) nmask |= (1 << j); | |
} | |
f[mask][cur] += solve(G, mask|(1<<i), i) * solve(G, mask|nmask, cur); | |
} | |
f[mask][cur] = max(1LL, f[mask][cur]); | |
} | |
return f[mask][cur]; | |
} | |
long long count(vector <string> G) { | |
memset(f, -1, sizeof(f)); | |
int n = G.size(); | |
long long ans = 0; | |
for (int i=0; i<n; i++) { | |
ans += solve(G, 1<<i, i); | |
cout<<solve(G, 1<<i, i)<<endl; | |
} | |
return ans; | |
} | |
}; |
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