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Testing std::list::remove_if() for memory organisation
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// | |
// Created by Barthap on 2019-01-22. | |
// | |
#include <utility> | |
#include <iostream> | |
#include <vector> | |
#include <list> | |
int main() | |
{ | |
std::list<int> lista = {1,2,3,4,5}; | |
for(auto& e : lista) | |
std::cout << e << " "; | |
std::cout << std::endl; | |
auto it = std::find(lista.begin(), lista.end(), 4); | |
int &ref = *it; | |
std::cout << "ref = " << ref << std::endl; | |
//std::remove_if(lista.begin(), lista.end(), [](auto& el) { return el == 2; }); | |
lista.remove_if([](auto& el) { return el == 2; }); | |
std::cout << "after remove, ref = " << ref << std::endl; | |
auto it2 = std::find(lista.begin(), lista.end(), 4); | |
std::cout << "Original address: " << std::addressof(ref) | |
<< "\nAfter remove: " << std::addressof(*it2) << std::endl; | |
ref = 16; | |
for(auto& e : lista) | |
std::cout << e << " "; | |
std::cout << std::endl; | |
} |
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