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bbookman/findThree.py

Created December 26, 2018 21:41
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Python List Comprehension: Find all of the numbers from 1-1000 that have a 3 in them
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findThree.py
'''
Find all of the numbers from 1-1000 that have a 3 in them
'''
three = [n for n in range(0,1000) if '3' in str(n)]
print(three)
@anasauram
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anasauram commented Jan 16, 2024 •
edited

These 3 options work:

x = [i for i in range(1, 1001) if str(i).find("3") != -1]
y = [i for i in range(1, 1001) if str(i).count("3") > 0]
z = [i for i in range(1, 1001) if '3' in str(i)]

print("x ->", x, len(x), "\n")
print("y ->", y, len(y), "\n")
print("z ->", z, len(z))

@SariCohen2
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You could also do it this way:
lst_include3=list(filter(lambda x: '3' in str(x), range(1,1000)))
print(lst_include3)

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