Python List Comprehension: Find numbers in sentence

nums_in_sentence.py

'''
Get only the numbers in a sentence like 'In 1984 there were 13 instances of a protest with over 1000 people attending'.  Result is a list of numbers like [3,4,5]
'''
sentence = 'In 1984 there were 13 instances of a protest with over 1000 people attending'
words = sentence.split()
result = [number for number in words if not number.isalpha() ]
print(result)

sentence = 'In 1984 there were 13 instances of a protest with over 1000 people attending' [int(letter) for letter in sentence if letter in ['1','2','3','4','5','6','7','8','9','0']]

Unfortunately, it does not work, because the question is not about digits

sentence = 'In 1984 there were 13 instances of a protest with over 1000 people attending'

numbers = [ num for num in sentence if num in [ str(x) for x in range(0,10)]

print(numbers)

your code will print digits, it's not question goal

string = "In 1984 there were 13 instances of a protest with over 13 people attending".split()
print(string)

list_a = [a for a in string if a[0] in ("1","2","3","4","5","6","7","8","9","0") ]
print(list_a)

# Get only the numbers in a sentence
sentence = 'In 1984 there were 13 instances of a protest with over 1000 people attending'
my_list = [item for item in sentence if item.isnumeric()]
print(my_list)

sentence = 'In 1984 there were 13 instances of a protest with over 1000 people attending'
#If we were about to return one integer at a time like [1, 9, 8, 4, 1, 3, 1, 0, 0, 0] rather than 1984, 13, 1000 we would do it like this:

nums = [number for number in sentence if number.isdigit() == True]
print(nums)