Minimal gulp file that will serve files from a public folder, open chrome for you, and live reload on changes

simple-gulpfile.js

var gulp = require('gulp'),
	livereload = require('gulp-livereload'),
	open = require('open'),
	express = require('express'),
	port = 80;

gulp.task('server', function(next){
	var server = express().use(express.static( __dirname + '/public' )).listen(port, next);
	var portStr = port == 80 ? '' : ':' + port;
	open("http://localhost" + portStr, "chrome");
});

gulp.task('default', ['server'], function(){
	var refresh = livereload();

	gulp.watch(['public/*.*', 'public/**/*.*']).on('change', function(file){
		refresh.changed(file.path);
	});

});

I'm tired of struggling with these complex generators that give me so much crap I don't need (don't know how to use). I think I'll just skip generators and use a simple live reload script like this.