Find all occurences of a key in a nested Python dictionary and return the occurences together with the keys

find_key_occurences.py

def find(find_object, result, keys=[]):
    if isinstance(find_object, dict):
        for key, value in find_object.iteritems():
            find(value, result, keys + [key])
    else:
        if not(result):
            result['values'] = [find_object]
            result['keys'] = [keys]
        else:
            result['values'].append(find_object)
            result['keys'].append(keys)


# Example 1
dict_example1 = {'key1': {'key1.1': ['value1.1.1','value1.1.2']},
                 'key2': 'value2',
                 'key3': {'key3.1': 'value3.1', 'key3.2': 'value3.2'},
                 'key4': ['value4.1', 'value4.2'],
                 'key5': {'key5.1': {'key5.1.1': ['value5.1.1.1']}}
                 }
# A result dictionary has to be provided, if this dictionary is
# declared in the function itself, the same object in memory keeps
# being addressing
result_example1 = {}

find(dict_example1, result_example1)

for i in range(len(result_example1['keys'])):
    print("keys: %s; values: %s" % (result_example1['keys'][i],
                                    result_example1['values'][i]))