Last active
December 27, 2015 03:39
-
-
Save benjaminliu/7261468 to your computer and use it in GitHub Desktop.
twitter water in walls problem
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
public class WaterBetweenNumberWalls { | |
public static void main(String[] args) { | |
int maxStorage = 0; | |
int[] nums = { 2, 5, 1, 3, 1, 2, 1, 7, 7, 6 }; | |
// int[] nums = { 2, 5, 1, 2, 3, 4, 7, 7, 6 }; | |
// int[] nums = { 2, 5, 1, 2, 3, 4, 7, 5, 6 }; | |
// int[] nums = { 6, 1, 4, 6, 7, 5, 1, 6, 4 }; | |
// int[] nums = { 2, 7, 2, 7, 4, 7, 1, 7, 3, 7 }; | |
maxStorage = GetMaxStorageImprove(nums); | |
System.out.println(maxStorage); | |
maxStorage = GetMaxStorage(nums); | |
System.out.println(maxStorage); | |
} | |
public static int GetMaxStorageImprove(int[] nums) { | |
int count = nums.length; | |
int leftIndex = 0; | |
int left = 0; | |
int rightIndex = 0; | |
int temp = 0; | |
int tempIndex = 0; | |
int right = 0; | |
int maxStorage = 0; | |
int storage = 0; | |
boolean isBreak = false; | |
// just like pop sort | |
for (leftIndex = 0; leftIndex < count - 1; leftIndex++) { | |
// Second one is bigger than first, cannot save water | |
if (nums[leftIndex + 1] > nums[leftIndex]) { | |
continue; | |
} | |
isBreak = false; | |
left = nums[leftIndex]; | |
temp = nums[leftIndex + 1]; | |
// max storage for one number | |
for (tempIndex = leftIndex + 2; tempIndex < count; tempIndex++) { | |
right = nums[tempIndex]; | |
if (right > temp) { | |
temp = right; | |
rightIndex = tempIndex; | |
if (right > left) { | |
isBreak = true; | |
break; | |
} | |
} | |
} | |
storage = GetStorage(nums, leftIndex, rightIndex); | |
if (storage > maxStorage) | |
maxStorage = storage; | |
// Water in walls between left and right will be smaller | |
if (isBreak == true) { | |
leftIndex = rightIndex - 1; | |
} | |
} | |
return maxStorage; | |
} | |
public static int GetMaxStorage(int[] nums) { | |
int count = nums.length; | |
int leftIndex = 0; | |
int left = 0; | |
int rightIndex = 0; | |
int temp = 0; | |
int tempIndex = 0; | |
int right = 0; | |
int maxStorage = 0; | |
int storage = 0; | |
// just like pop sort | |
for (leftIndex = 0; leftIndex < count - 1; leftIndex++) { | |
// Second one is bigger than first, cannot save water | |
if (nums[leftIndex + 1] > nums[leftIndex]) { | |
continue; | |
} | |
left = nums[leftIndex]; | |
temp = nums[leftIndex + 1]; | |
// max storage for one number | |
for (tempIndex = leftIndex + 2; tempIndex < count; tempIndex++) { | |
right = nums[tempIndex]; | |
if (right > temp) { | |
temp = right; | |
rightIndex = tempIndex; | |
if (right > left) { | |
break; | |
} | |
} | |
} | |
storage = GetStorage(nums, leftIndex, rightIndex); | |
if (storage > maxStorage) | |
maxStorage = storage; | |
} | |
return maxStorage; | |
} | |
public static int GetStorage(int[] nums, int l, int r) { | |
int storage = 0; | |
if (nums[r] > nums[l]) { | |
storage = nums[l] * (r - l - 1); | |
} else { | |
storage = nums[r] * (r - l - 1); | |
} | |
for (int i = l + 1; i < r; i++) { | |
storage -= nums[i]; | |
} | |
return storage; | |
} | |
} |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment